A) 18 m
B) 6 m
C) \[\frac{2}{3}\,m\]
D) \[\frac{2}{9}\,m\]
Correct Answer: A
Solution :
\[{{H}_{\max }}=\frac{{{u}^{2}}}{2g}\Rightarrow {{H}_{\max }}\propto \frac{1}{g}\] On planet 5 value of g is 1/9 times to that of A So value of \[{{H}_{\max }}\]will become 9 times i.e.,\[2\times 9=18\] metre
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