NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    Consider the following reactions:
    (i)\[{{H}^{+}}(aq)+O{{H}^{-}}(aq)\to {{H}_{2}}O(l);\] \[\Delta H =-{{X}_{1}}\,kJ\,mo{{l}^{-1}}\]
    (ii) \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\to {{H}_{2}}O(l);\] \[\Delta H =-{{X}_{2}}\,kJ\,mo{{l}^{-1}}\]
    (iii) \[C{{O}_{2}}(g)+{{H}_{2}}(g)\to CO(g)+{{H}_{2}}O(l);\] \[\Delta H =-{{X}_{3}}kJ\,mo{{l}^{-1}}\]
    (iv) \[{{C}_{2}}{{H}_{2}}(g)+\frac{5}{2}{{O}_{2}}(g)\to 2C{{O}_{2}}g+{{H}_{2}}O(l);\] \[\Delta H =+{{X}_{4}}\,kJ\,mo{{l}^{-1}}\]
    Enthalpy of formation of \[{{H}_{2}}O(l)\] is

    A) \[-{{x}_{2}}\,\,kJ\,mo{{l}^{-1}}\]

    B) \[+{{x}_{3}}\,\,kJ\,mo{{l}^{-1}}\]

    C) \[-{{x}_{4}}\,\,kJ\,mo{{l}^{-1}}\]

    D) \[-{{x}_{1}}\,\,kJ\,mo{{l}^{-1}}\]    

    Correct Answer: A

    Solution :

    The amount of heat evolved or absorbed during the formation of 1 mole of a compound from its constituent is known as heat of formation. So, the correct answer is \[{{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\to {{H}_{2}}O(l);\,\Delta H =-{{X}_{2}}\,kJ\,mo{{l}^{-1}}\]


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