A) 605.3 m
B) 600 m
C) 80 m
D) 230 m
Correct Answer: A
Solution :
The horizontal distance covered by bomb, \[BC\,\,=\,\,{{v}_{H}}\,\times \,\,\sqrt{\frac{2h}{g}}\,\,=\,\,150\,\sqrt{\frac{2\,\,\times \,\,80}{10}}\,\,=\,\,660\,m\] \[\therefore \] The distance of target from dropping point of bomb, \[AC\,\,=\,\,\sqrt{A{{B}^{2}}+B{{C}^{2}}}\,\,=\,\,\sqrt{{{(80)}^{2}}+{{(600)}^{2}}}=\,\,605.3\,m\]You need to login to perform this action.
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