A) 7.46J
B) 7400J
C) 7.46erg
D) 74.6J
Correct Answer: A
Solution :
\[\eta =\frac{{{P}_{o}}}{{{P}_{1}}}\] \[{{P}_{o}}=\frac{W}{t}=\eta {{\operatorname{P}}_{1}}\] \[\frac{W}{2\pi \times 600\times \frac{2}{60}\pi }=\frac{40}{100}\times \frac{746}{4}\] 1 HP =746 WATT W=7.46 JouleYou need to login to perform this action.
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