A) 5R
B) 15R
C) 3R
D) 4R
Correct Answer: C
Solution :
\[\operatorname{Force}\,\,=W=\frac{GMm}{{{R}^{2}}}\] \[\frac{W}{16}=\frac{GMm}{{{\left( R+H \right)}^{2}}}\] \[(1)\div (2)\] \[16={{\left( \frac{R+H}{R} \right)}^{2}}\]You need to login to perform this action.
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