A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
3 \[{{\operatorname{C}}_{5}}{{H}_{8}}\] \[1.\,\,CH{{ & }_{3}}C{{H}_{2}}C{{H}_{2}}C=CH\] \[2.\,\,{{\left( C{{H}_{3}} \right)}_{2}}CH-C=CH\] \[3. \,C{{H}_{3}}C{{H}_{2}}C=CC{{H}_{3}}\]You need to login to perform this action.
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