question_answer

2nd overtone of an open organ pipe resonate with 3rd harmonics of a closed organ pipe. The ratio of their length will be:

A)  \[\frac{2}{1}\]                       

B)  \[\frac{1}{2}\]

C)  \[\frac{6}{5}\]                       

D)  \[\frac{5}{6}\]

Correct Answer: A

Solution :

As   \[\frac{{{L}_{1}}}{{{L}_{2}}}=\frac{3\lambda /2}{3\lambda /4}=\frac{2}{1}\]