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NEET Sample Paper NEET Sample Test Paper-4

  • question_answer
    If photons of energy \[12.75\text{ }eV\] are passing through hydrogen gas in ground state, then number of lines in emission spectrum will be:

    A)  6                    

    B)  4

    C)  3                    

    D)  2

    Correct Answer: A

    Solution :

    From the concept of ionization energy \[12.75={{E}_{0}}-\frac{{{E}_{0}}}{{{n}^{2}}}=-13.6-\frac{(-13.6)}{n_{1}^{2}}\]             \[\Rightarrow \]   \[n=4\] number of lines \[=\frac{n(n-1)}{2}=6\]


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