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NEET Sample Paper NEET Sample Test Paper-4

  • question_answer
    The equilibrium concentration for the reaction\[C{{O}_{(g)}}+C{{l}_{2(g)}}COC{{l}_{2(g)}}\] at \[{{74}^{o}}C\] are  \[[CO]=1.2\times {{10}^{-2}}M,\] \[[C{{l}_{2}}]=5.4\times {{10}^{-2}}M,\] \[[COC{{l}_{2}}]=0.014\,M.\] What is the value of\[{{K}_{p}}\]?

    A)  \[21.6\]                       

    B)  \[7.584\]

    C)  \[4.578\]                     

    D)  \[75.84\]

    Correct Answer: B

    Solution :

    \[C{{O}_{(g)}}+C{{l}_{2(g)}}COC{{l}_{2}}\,(g)\] \[{{K}_{C}}=\frac{[COC{{l}_{2}}]}{[CO]\,[C{{l}_{2}}]}\] \[=\frac{0.4}{1.2\times {{10}^{-2}}\times 5.4\times {{10}^{-2}}}=216.05\] \[{{K}_{P}}={{K}_{C}}(RT)\Delta {{n}_{g}}\] \[\Delta {{n}_{g}}=-1\] \[{{K}_{P}}={{K}_{C}}{{(RT)}^{-1}}=\frac{{{K}_{C}}}{RT}\] \[{{K}_{P}}=\frac{216.05}{0.0821\times 347}=7.584\]


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