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NEET Sample Paper NEET Sample Test Paper-4

  • question_answer
    For a cell reaction involving a two electron change the standard emf of the cell is found to be \[0.295\text{ }V\]at\[{{25}^{o}}\text{ }C\]. The equilibrium constant for the reaction at \[{{25}^{o}}\text{ }C\] will be:

    A)  \[1\times {{10}^{-10}}\]                

    B)  \[29.5\times {{10}^{2}}\]

    C)  10                              

    D)  \[1\times {{10}^{10}}\]            

    Correct Answer: D

    Solution :

    \[{{E}^{o}}_{cell}=\frac{0.0591}{n}\,\log \,{{K}_{C}}\] \[0.295=\frac{0.0591}{2}\log \,{{K}_{C}}\] \[\frac{0.590}{0.0591}=\log \,{{K}_{C}}\] \[{{K}_{C}}=1\times {{10}^{10}}\]


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