A) \[21.6\]
B) \[7.584\]
C) \[4.578\]
D) \[75.84\]
Correct Answer: B
Solution :
\[C{{O}_{(g)}}+C{{l}_{2(g)}}COC{{l}_{2}}\,(g)\] \[{{K}_{C}}=\frac{[COC{{l}_{2}}]}{[CO]\,[C{{l}_{2}}]}\] \[=\frac{0.4}{1.2\times {{10}^{-2}}\times 5.4\times {{10}^{-2}}}=216.05\] \[{{K}_{P}}={{K}_{C}}(RT)\Delta {{n}_{g}}\] \[\Delta {{n}_{g}}=-1\] \[{{K}_{P}}={{K}_{C}}{{(RT)}^{-1}}=\frac{{{K}_{C}}}{RT}\] \[{{K}_{P}}=\frac{216.05}{0.0821\times 347}=7.584\]You need to login to perform this action.
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