NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    The horizontal range and maximum height attained by a projectile are R and H respectively.   If   a   constant   horizontal acceleration \[a=g/4\] is imparted to the projectile due to wind, then its horizontal range and maximum height will be-

    A) \[(R+H),\,\frac{H}{2}\]

    B)                \[\left( R+\frac{H}{2} \right),\,\,2H\]

    C) \[\left( R+2H \right),\,\,H\]                      

    D) \[\left( R+H \right),\,\,H\]

    Correct Answer: D

    Solution :

    \[R\,\,=\,\,\,{{u}_{x}}t+\frac{1}{2}\,\,{{a}_{x}}{{t}^{2}}\] \[=\,\,u\,\cos \theta \,\,\times \,\,\frac{2u\,\sin \,\theta }{g}\,\,+\,\,\frac{1}{2}\,\,\left( \frac{g}{4} \right)\,\,{{\left( \frac{2u\,\sin \,\theta }{g} \right)}^{2}}\] \[=\,\,\frac{2{{u}^{2}}\sin \,\theta \,\cos \,\theta }{g}\,\,+\,\,\frac{{{(u\,sin\,\theta )}^{2}}}{2g}\] \[=\,\,R\,\,+\,\,H,\,\,R\,\,\,\,=\,\,\,\frac{2{{u}^{2}}\,\sin \,\theta \,\cos \,\theta }{g}\] \[H\,\,=\,\,\frac{{{(u\,\sin \,\theta )}^{2}}}{2g}\]  


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