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NEET Sample Paper NEET Sample Test Paper-54

  • question_answer
    Two identical capacitors, have the same capacitance C. One of them is charged to potential \[{{V}_{1}}\] and the other to\[{{V}_{2}}\]. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is-

    A) \[\frac{1}{4}\,\,C\,(V_{1}^{2}-V_{2}^{2})\]    

    B) \[\frac{1}{4}\,\,C\,(V_{1}^{2}+V_{2}^{2})\]

    C) \[\frac{1}{4}\,\,C\,\,{{({{V}_{1}}-{{V}_{2}})}^{2}}\]

    D)  \[\frac{1}{4}\,\,C\,\,{{({{V}_{1}}+{{V}_{2}})}^{2}}\]

    Correct Answer: C

    Solution :

    \[\Delta U=\frac{1}{2}\,\,\left( \frac{{{C}_{1}}{{C}_{2}}}{{{C}_{1}}+{{C}_{2}}} \right){{({{V}_{1}}-{{V}_{2}})}^{2}}\]


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