A) \[+\frac{1}{2}\frac{h}{2\pi }\]
B) \[Zero\]
C) \[\frac{h}{2\pi }\]
D) \[Three\]
Correct Answer: B
Solution :
[b] Zero Orbital angular momentum \[=\sqrt{1(1+1)}\frac{h}{2\pi }\] \[\therefore \] For 2s orbital, \[l=0\] Therefore Capital angular momentum \[=\sqrt{0(0+1)}\frac{h}{2\pi }=\frac{0h}{2\pi }=0\]You need to login to perform this action.
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