A) Decreasing Ip-bp repulsion
B) Decreasing electronegativity
C) Increasing Ip-bp repulsion
D) Increasing p-orbital character in \[S{{p}^{3}}\]
Correct Answer: B
Solution :
[b] Decreasing electronegativity Decreasing values of bond angles from \[N{{H}_{3}}({{106}^{{}^\circ }})\]to\[Sb{{H}_{3}}{{(101)}^{{}^\circ }}\]increases the electronegativity. Then bond pairs move farther and farther away from the central atom. As a result, bp-bp repulsion decreases and the angle decreases accordingly.You need to login to perform this action.
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