A) 84.72%
B) 64%
C) 92%
D) 72%
Correct Answer: A
Solution :
[a] 84.72% Mass of solution = Mass of \[{{C}_{6}}{{H}_{6}}\]+mass of \[CC{{l}_{4}}\] \[=22g+122g\] \[=144g\] \[Mass\,\,of\,%\,of\,benzene\,=\frac{Mass\,of\,benzene}{Mass\,of\,solution\,}\times 100\] \[=\frac{22}{144}\times 100=15.28%\] \[Mass\,%\,of\,CC{{l}_{4}}=\frac{Mass\,of\,CC{{l}_{4}}}{Mass\,of\,solution}\times 100\,\] \[=\frac{122}{144}\times 100=84.72%\]You need to login to perform this action.
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