A) - 12KJ
B) 20KJ
C) - 20KJ
D) 20J
Correct Answer: C
Solution :
[c] \[n=1,\gamma \,[diotomic]\frac{7}{5}\] \[\Delta U=n{{C}_{v}}\Delta T\,[always]\] \[n{{C}_{v}}[{{T}_{2}}-{{T}_{1}}]\] \[=n\frac{R}{y-1}\,[{{T}_{2}}-{{T}_{1}}]\] \[=\frac{{{P}_{2}}{{V}_{2}}-{{P}_{1}}{{V}_{1}}}{\gamma -1}\] \[=\frac{2\times {{10}^{3}}\times 6-5\times {{10}^{3}}\times 4}{\frac{7}{5}-1}\] \[=\frac{{{10}^{2}}}{2}\times 5\,[12-20]\Rightarrow -20KJ\] \[{{C}_{v}}=\frac{R}{\gamma -1}\] \[{{C}_{p}}=\frac{\gamma R}{\gamma -1}\]You need to login to perform this action.
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