A) 12sec
B) 3 sec
C) 2 sec
D) 8 sec
Correct Answer: C
Solution :
[c] Particle starts from mean position hence equation of motion used will be of sin \[x=A\,\sin \,\omega t[\phi =0]\] \[0.1=0.2\,\sin \,\frac{2\pi t}{T}\] \[0.1=0.2\,\sin \,\frac{2\pi t}{T}\] \[Sin\,\frac{\pi }{6}=Sin\,\frac{\pi t}{12}\] \[t=2\,\sec \] Note Particle starts from mean position use \[x=A\,\sin \,\omega \] If particle starts from any position except mean, use \[x=A\,\cos \,(\omega t+\phi )\]You need to login to perform this action.
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