A) 22C
B) 20C
C) 18C
D) 5C
Correct Answer: A
Solution :
[a] \[I=3{{t}^{2}}+2t+5\] \[\frac{dq}{dt}=3{{t}^{2}}+2t+5\] \[dq=(3{{t}^{2}}+2t+5)dt\] \[\int{dq=\int\limits_{0}^{2}{3{{t}^{2}}dt+\int\limits_{0}^{2}{2t\,dt+\int\limits_{0}^{2}{4dt}}}}\] \[q=\left[ \frac{3\times {{t}^{2}}}{3} \right]_{0}^{2}+\left[ \frac{2{{t}^{2}}}{2} \right]_{0}^{2}+5\,[t]_{0}^{2}\] \[=(4-0)+(4-0)+5(2-0)=22C\]You need to login to perform this action.
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