question_answer

A conductor in the form of the right triangle ABC with \[AB=3cm\]and \[BC=4cm\]carries a current of 10A. There is a uniform magnetic field of 5T perpendicular to the plane of the conductor. The force on the conductor AC will be:

A)  \[1.5\,N\]                    

B)  \[2.0\,N\]

C)  \[2.5\,N\]                    

D)  \[3.5\,N\]

Correct Answer: C

Solution :

Force on the conductor ABC = Force on the conductor AC             \[=5\times 10\times (5\times {{10}^{-2}})=2.5N\]