NEET Sample Paper NEET Sample Test Paper-5

  • question_answer
    Two concentric conducting spheres having radii a and b are charged to \[{{q}_{1}}\] and \[{{q}_{2}}\] respectively. The potential difference between 1 and 2 will be:            

    A)  \[\frac{{{q}_{1}}}{4\pi {{\varepsilon }_{0}}a}-\frac{{{q}_{2}}}{4\pi {{\varepsilon }_{0}}b}\]           

    B)  \[\frac{{{q}_{2}}}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{a}-\frac{1}{b} \right)\]

    C)                  \[\frac{{{q}_{1}}}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{a}-\frac{1}{b} \right)\]           

    D)  None of these

    Correct Answer: C

    Solution :

    The potential on the surface of the sphere 1 is given by \[{{V}_{1}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}}{a}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{2}}}{b}\]                ?..(i) The potential on the surface of the sphere 2 is given by             \[{{V}_{2}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}}{a}+\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{2}}}{p}\]            ?..(ii) Now potential difference,             \[V={{V}_{1}}-{{V}_{2}}\] \[\Rightarrow \]               \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}}{a}-\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}}{b}\] \[\Rightarrow \]               \[V=\frac{{{q}_{1}}}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{a}-\frac{1}{b} \right)\]


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