A) orange
B) brown
C) red
D) colourless
Correct Answer: D
Solution :
\[HgC{{l}_{2}}+2KI\xrightarrow{{}}2KCl+\underset{scarlet\,\,ppt}{\mathop{Hg{{I}_{2}}}}\,\] \[Hg{{I}_{2}}+\underset{excess}{\mathop{2KI}}\,\xrightarrow{{}}\underset{colourless\,\,complex}{\mathop{{{K}_{2}}Hg{{I}_{4}}}}\,\]You need to login to perform this action.
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