A) 0.6 mole
B) 0.8 mole
C) 0.2 mole
D) 0.4 mole
Correct Answer: B
Solution :
[b] 0.8 mole \[{{N}_{2}}+3{{H}_{2}}2N{{H}_{3}}\] formation of 0.8 mole of \[N{{H}_{3}}\] means that \[\frac{3}{2}\times 0.8\] mole of \[{{H}_{2}}\] have reacted. Hence, concentration of \[{{H}_{2}}=2-\frac{3}{2}\times 0.8\] \[=2-3\times 0.4\] \[=2-1.2=0.8\,mole\]You need to login to perform this action.
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