A) \[2.0\times {{10}^{-}}^{20}\,J\]
B) \[2.2\times {{10}^{-}}^{19}\,J\]
C) \[2.0\times {{10}^{-}}^{19}\,J\]
D) \[4.0\times {{10}^{-}}^{20}\,J\]
Correct Answer: A
Solution :
KE of molecule = energy absorbed by molecule - BE per molecule \[=\,\,\left( 4.4\times {{10}^{-1}}^{9} \right)-\left( 4.0\times {{10}^{-}}^{19} \right)\,J=\,\,0.4\times {{10}^{-19}}\,J\] KE per atom \[=\,\,\frac{0.4\times {{10}^{-19}}}{2}\,\,J=\,\,2.0\,\,\times \,\,\,{{10}^{-20}}J\]You need to login to perform this action.
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