A) 0.805 M, 4.83 N, 0.825 m
B) 0.825 M, 48.3 N, 0.805 m
C) 4.83 M, 4.83 N, 4.83 m
D) None
Correct Answer: A
Solution :
\[Molarity\,\,=\,\,\frac{%\,\times 10\times d}{GMM}\] \[=\,\,\,\frac{22\times 10\times 1.253}{342}\,=\,0.805\,\,M\] \[Normality\,\,=\,\frac{%\times 10\times d}{GEM}\] \[=\,\,\frac{22\times 10\times 1.253}{342/6}\,=\,4.83\,N\] \[Molality\,\,=\,\,\frac{22\times 1000}{342(100-22)}\,\,=\,\,0.825\,m\]You need to login to perform this action.
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