A) \[{{A}_{7}}{{B}_{6}}\]
B) \[{{A}_{6}}{{B}_{7}}\]
C) \[{{A}_{7}}{{B}_{24}}\]
D) \[A{{B}_{4}}\]
Correct Answer: D
Solution :
Since there are six atoms in the corner of the unit cell. So, contribution of atoms in 1 unit cell is \[\frac{6}{8}\]. Since 3 face-centered atoms contributes to one unit cell So, formula is \[{{\operatorname{Ag}}_{6/8}}\,{{B}_{3}}\] or \[{{A}_{6}}\,{{B}_{24}},\,\,\,\,\,or\,\,\,\,\,\,A{{B}_{4}}\]You need to login to perform this action.
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