A) \[-0.31{}^\circ C\]
B) \[-0.45{}^\circ C\]
C) \[-0.53{}^\circ C\]
D) \[-0.90{}^\circ C\]
Correct Answer: B
Solution :
\[\Delta {{T}_{f}}=molality\,\,\times \,\,{{K}_{f}}\times (1+\alpha )\] \[\alpha =0.2\,\,Molality=0.2,\,\,{{K}_{f}}=1.86\] \[\Delta {{T}_{f}}= 0.2 \times 1.2 \times 1.86 = 0.4464\] \[Freezing point = -0.45{}^\circ C.\]You need to login to perform this action.
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