A) \[2.0\times {{10}^{18}}\,{{s}^{-1}}\]
B) \[6.0\times {{10}^{14}}\,{{s}^{-1}}\]
C) Infinity
D) \[3.6\times {{10}^{30}}\,{{s}^{-1}}\]
Correct Answer: B
Solution :
The Arrhenius equation is \[K=A{{e}^{-Ea/RT}}\] As \[T\to \infty \,\,the\,\,value\,\,\frac{Ea}{RT}\to 0\] Therefore, \[{{e}^{-Ea/RT}}\to {{e}^{-\,0}}\Rightarrow 1\] Hence \[k\to A\] Hence \[k\,\,=\,\,6.0\times {{10}^{14}}{{s}^{-1}}\]You need to login to perform this action.
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