question_answer

      In the circuit shown, the equivalent capacitance between the point A and B is:

A)  \[\frac{10}{3}\mu F\]               

B)  \[\frac{15}{4}\mu F\]

C)  \[\frac{12}{5}\mu F\]                   

D)  \[\frac{25}{6}\mu F\]

Correct Answer: A

Solution :

Since, \[\frac{3}{2}=\frac{6}{4}\] the circuit is treated as Wheatstone bridge                 \[{{C}_{eq}}=\frac{3\times 6}{3+6}+\frac{2\times 4}{2+4}=2+\frac{8}{6}=\frac{20}{6}=\frac{10}{3}\mu F\]