A) \[6.63\times {{10}^{-27}}kg\,m/s\]
B) \[2\times {{10}^{-27}}kg\,m/s\]
C) \[{{10}^{-27}}kg\,m/s\]
D) None of these
Correct Answer: B
Solution :
The momentum of the incident radiation is given as \[P=\frac{h}{\lambda }\] When the light is totally reflected normal to the surface, the direction of the ray is reversed. That means it reverses the direction of its momentum without changing its magnitude change in momentum has a magnitude. \[\Delta p=P-(-P)=2P=\frac{2h}{\lambda }\] \[\Rightarrow \] \[\Delta p=\frac{2(6.63\times {{10}^{-34}}J-s)}{(66.30\times {{10}^{-10}}m)}\] \[\Rightarrow \] \[\Delta p=2\times {{10}^{-27}}kgm/s\]
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