A) Diamine dichloroplatinum (II)
B) Tetraamine dichlorocobalt (III) chloride
C) Potassium hexacyanoferrate (II)
D) Pentacarbonyl iron (O)
Correct Answer: C
Solution :
Potassium hexa cyanoferrate (II) i.e. \[{{K}_{4}}[Fe{{(CN)}_{6}}]\] gives the maximum number of ions on ionisation hence it has the highest molar conductivity. \[{{K}_{4}}\left[ Fe{{(CN)}_{6}} \right]\xrightarrow{{}}4{{K}^{+}}+{{\left[ Fe{{(CN)}_{6}} \right]}^{4-}}\]
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