A) \[{{\sin }^{-1}}\,\left( {{n}_{2}}/{{n}_{1}} \right)\]
B) \[{{\sin }^{-1}}\,\sqrt{n_{1}^{2}-n_{2}^{2}}\]
C) \[\left[ {{\tan }^{-1}}\frac{{{n}_{2}}}{{{n}_{1}}} \right]\]
D) \[\left[ {{\tan }^{-1}}\frac{{{n}_{1}}}{{{n}_{2}}} \right]\]
Correct Answer: B
Solution :
When light is launched at one end of a step index optical fibre, then the illustration of the path of light ray incident on the end of an optical fibre at an angle to the fibre axis is as shown Acceptance angle is the maximum angle that a light ray can have relative to the axis of the fibre and propagate down the fibre. It is given by \[\theta ={{\sin }^{-1}}\,\sqrt{n_{1}^{2}-n_{2}^{2}}\]You need to login to perform this action.
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