A) 58
B) 29
C) 116
D) 14.5
Correct Answer: B
Solution :
Element belongs to 2nd group and 3rd period is Mg. Mg on burning in air given MgO whose aqueous solution is basic in nature due to formation of \[\operatorname{Mg}{{\left( OH \right)}_{2}}\]. Molecular mass of \[\operatorname{Mg}\,{{(OH)}_{2}}\,\,=\,\,24+17\times 2\] \[= 24 + 34 = 58\] Equivalent weight of \[\operatorname{Mg}{{\left( OH \right)}_{2}}=\frac{58}{2}=29\]You need to login to perform this action.
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