A) \[3\text{ }RC\]
B) \[2/3\text{ }RC\]
C) \[6RC/S\]
D) \[2RC\]
Correct Answer: C
Solution :
From the circuit diagram \[{{R}_{eff}}=\frac{2R\times 3R}{2R+3R}=\frac{6}{5}R\] \[\Rightarrow \] \[\tau =C.{{R}_{eff}}=\frac{6RC}{5}\]
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