A) \[\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{2}}+\left( 1-\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{1}}\]
B) \[\left( 1+\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1+\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{2}}\]
C) \[\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1-\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{2}}\]
D) \[\left( 1+\frac{1}{{{\mu }_{1}}} \right){{h}_{2}}+\left( 1+\frac{1}{{{\mu }_{2}}} \right)\,{{h}_{1}}\]
Correct Answer: C
Solution :
Apparent shift \[\Delta h=\left( 1-\frac{1}{u} \right)h\] \[\therefore \] Apparent shift produced in water is \[\Delta {{h}_{1}}=\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}\]and apparent shift produced , by liquid is \[\Delta {{h}_{2}}\,=\,\,\left( 1-\frac{1}{{{\mu }^{2}}} \right){{h}_{2}}\] \[\Delta h\,\,=\,\,\Delta {{h}_{1}}+\Delta {{h}_{2}}=\left( 1-\frac{1}{{{\mu }_{1}}} \right){{h}_{1}}+\left( 1-\frac{1}{{{\mu }^{2}}} \right){{h}_{2}}\]You need to login to perform this action.
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