A) \[{{x}^{2}}L\]
B) \[z{{L}^{2}}\]
C) \[y{{L}^{2}}\]
D) \[x{{L}^{2}}\]
Correct Answer: D
Solution :
Given, \[\operatorname{E}=x\,\hat{i}\,+y\hat{j}\,\,+\,\,z\hat{k}\] Now, a square of side L parallel to y-z plane in vector form can be written as \[S\,\,=\,\,{{L}^{2}}\,\hat{i}\] Now, electric flux passing through given area will be \[\phi =E\cdot S\] \[=\,\,\,(x\hat{i}\,\,+\,\,y\hat{j}\,\,+\,\,z\hat{k})\,\cdot \,({{L}^{2}}\,\hat{i})\] \[=\,\,\,x\,{{L}^{2}}\]You need to login to perform this action.
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