A) 8%
B) 12%
C) 32%
D) 25%
Correct Answer: C
Solution :
[c] Given, \[P={{a}^{1/2}}{{b}^{2}}{{c}^{3}}{{d}^{-4}}\] Maximum relative error, \[\frac{\Delta P}{P}=\frac{1}{2}\frac{\Delta a}{a}+2\frac{\Delta b}{b}+3\frac{\Delta c}{c}+4\frac{\Delta d}{d}\] \[=\frac{1}{2}\times 2+2\times 1+3\times 3+4\times 5=32%\]You need to login to perform this action.
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