A) \[\frac{R}{\sqrt{2}}\]
B) \[\frac{R}{\sqrt{3}}\]
C) \[R\sqrt{2}\]
D) \[R\]
Correct Answer: D
Solution :
Given, \[\frac{{{\mu }_{0}}i{{R}^{2}}}{2{{({{R}^{2}}+{{X}^{2}})}^{3/2}}}=\frac{1}{\sqrt{8}}\frac{\mu {{'}_{0}}}{2R}\] \[{{({{R}^{2}}+{{X}^{2}})}^{3/2}}={{R}^{3}}\sqrt{8}\] \[({{R}^{2}}+{{X}^{2}})=8{{R}^{6}}\] \[X=\pm R\] (Here, \[-R\] is neglected)
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