2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-8

  • question_answer
    The volume of \[C{{l}_{2}}\] at S.T.P. obtained on reacting \[4.35\text{ }g\] \[~Mn{{O}_{2}}\]with cone. \[HCl\] (at. wt. of \[Mn=55\]) is

    A)  \[4.48\]litre                 

    B)  \[2.24\]litre

    C)  \[1.12\]litre           

    D)  \[0.56\]litre

    Correct Answer: C

    Solution :

    \[\underset{\begin{smallmatrix}  55+32 \\  =\,87\,g \end{smallmatrix}}{\mathop{Mn{{O}_{2}}}}\,+4HCl\xrightarrow{{}}MnC{{l}_{2}}+2{{H}_{2}}O+\underset{22.4\,L}{\mathop{C{{l}_{2}}}}\,\] \[C{{l}_{2}}\] produced from \[4.35\text{ }g\text{ }Mn{{O}_{2}}\]                 \[=\frac{22.4}{87}\times 4.35=1.12\,L\]


You need to login to perform this action.
You will be redirected in 3 sec spinner