A) 166
B) 83
C) 140
D) 280
Correct Answer: C
Solution :
[c] Total V.P., \[P=P_{A}^{{}^\circ }{{X}_{A}}+P_{B}^{{}^\circ }{{X}_{B}}=P_{A}^{{}^\circ }{{X}_{A}}+P_{B}^{{}^\circ }(1-{{X}_{A}})\] \[=(P_{A}^{{}^\circ }-P_{B}^{{}^\circ }){{X}_{A}}+P_{B}^{{}^\circ }\] Thus, \[P_{B}^{{}^\circ }=114\,\,torr;\] \[P_{A}^{{}^\circ }-P_{B}^{{}^\circ }=52\] or \[P_{A}^{{}^\circ }=166\,\,torr\] Hence \[P=166\times \frac{1}{2}+114\times \frac{1}{2}=140\,\,torr\]You need to login to perform this action.
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