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NEET Sample Paper NEET Sample Test Paper-9

  • question_answer
    A wire at bent to form a semi-circle of radius. The wire rotates about its one and with angular velocity \[\omega \] axis of rotation being perpendicular to plane of the semicircle. In the space, uniform magnetic field of induction B exists along the axis of rotation as shown. The correct statement is:

    A)  Potential difference between P and Q is equal to \[2B\omega {{a}^{2}}\]

    B)  Potential difference between P and Q is equal to \[2{{\pi }^{2}}B\omega {{a}^{2}}\]

    C)  P, is at higher potential than Q

    D)  Potential difference between P and Q is zero

    Correct Answer: A

    Solution :

    As,   emf  \[\varepsilon =V\,BL\] \[=\frac{1}{2}B{{l}^{2}}\omega =\frac{1}{2}B{{(2a)}^{2}}\omega =2B\omega {{a}^{2}}\] (\[\therefore \]\[L=L/2\] and \[V=\omega r=\omega l/2\])


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