A) \[5\times {{10}^{16}}hz\]
B) \[1.5\times {{10}^{27}}hz\]
C) \[0.5\times {{10}^{18}}hz\]
D) \[5\times {{10}^{18}}hz\]
Correct Answer: B
Solution :
\[E=m{{c}^{2}}\] \[E=h\upsilon \] \[m{{c}^{2}}=h\upsilon \] \[\upsilon =\frac{m{{c}^{2}}}{h}=\frac{1.1\times {{10}^{-23}}\times {{(3\times {{10}^{8}})}^{2}}}{6.6\times {{10}^{-34}}}\] \[=1.5\times {{10}^{27}}{{h}_{z}}\]
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