A) \[0.1\,R\]
B) \[2.303\text{ }R\]
C) \[10.0\text{ }R\]
D) 100.0 R
Correct Answer: B
Solution :
\[{{q}_{rev}}=-{{W}_{rev}}=2.303\,nRT\,\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[\Delta S=\frac{{{q}_{rev}}}{T}=2.303\,\,n\,R\,\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[n=1\] \[\frac{{{V}_{2}}}{{{V}_{1}}}=10\] \[\Delta S=2.303\times 1\times R\times \log \,10\] \[=2.303\times R\times 1\] \[=2.303\,R\]
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