A) magnetic moment
B) co-ordination number and oxidation states
C) structure
D) colour
Correct Answer: B
Solution :
In \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] the hybridisation of \[Ni\] is \[ds{{p}^{2}}\](square planar) having no unpaired electron while in \[{{[NiC{{l}_{4}}]}^{-}}\,\,Ni\] is present in \[s{{p}^{3}}\]hybridisation (tetrahedral) with 2 unpaired electrons. Hence these two complexes differ in magnetic moment, structure, and colour but they have similar coordination number (i.e. 4) and oxidation state (i.e. \[+2\])
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