NTSE Sample Paper NTSE SAT Practice Test-4

  • question_answer
    V = volume of the right circular cylinder
    S = Surface area of right circular cylinder
    h = height of the cylinder
    \[r=1\] unit
    Then \[\frac{V}{S}\] is equal to

    A)  \[\frac{1}{2}\left( 1-\frac{1}{h} \right)\]                               

    B)  \[\frac{1}{2}\left( 1+\frac{1}{h} \right)\]

    C)  \[\frac{1}{2}\left( 1-\frac{1}{h+1} \right)\]          

    D)  \[\frac{1}{2}\left( 1+\frac{1}{h+1} \right)\]

    Correct Answer: C


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