question_answer

If sum of the first M-natural numbers is \[\frac{n(n+1)}{2}\], then the sum of first In odd natural numbers will be

A)  \[{{\left[ \frac{n(n+1)}{2} \right]}^{2}}\]              

B)  \[4{{n}^{2}}+1\]

C)  \[4{{n}^{2}}\]                                   

D)  \[n(n+1)\]