A) \[60.25\,c{{m}^{2}}\]
B) \[70\,c{{m}^{2}}\]
C) \[80\,c{{m}^{2}}\]
D) \[48\,c{{m}^{2}}\]
Correct Answer: D
Solution :
[d]AB=AC=x, BC=32-2x \[\therefore \] BD = 16 - x, Also AD = 8 (given) \[A{{B}^{2}}=B{{D}^{2}}+A{{D}^{2}}\] \[\Rightarrow {{x}^{2}}={{8}^{2}}+{{(16-x)}^{2}}\]which gives x =10. \[\therefore \text{ }BC=32-20=12\,\,cm.\] Area of the triangle \[=\frac{1}{2}~~BC\times AD~\] \[=\frac{1}{2}\times 12\times 88\,\,\,c{{m}^{2}}=48\,\,c{{m}^{2}}\]You need to login to perform this action.
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