A) 3
B) 2
C) 0
D) -2
Correct Answer: B
Solution :
[b] \[{{2}^{2x-1}}=\frac{1}{{{8}^{x-3}}}\Rightarrow {{2}^{2x-1}}={{2}^{-3(x-3)}}\] \[\therefore \,\,\,2x-1=-\,3\,(x-3)\] \[\Rightarrow \,\,5x=10\,\,orx=2\]You need to login to perform this action.
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