A) \[r+p\]
B) p-q
C) \[2r-p\]
D) r-p
Correct Answer: D
Solution :
[d] Since (x -k) is a factor of both expressions, so \[q{{k}^{2}}+2k\text{ + }p=0\]and \[q{{k}^{2}}+k+r=0\]and on subtraction, we get \[k=r-p.\]You need to login to perform this action.
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