Answer:
The angular separation of nth maxima is given by \[{{\theta }_{n}}=n\lambda /d\] For 10th maxima, the angular separation, \[{{\theta }_{10}}=\frac{10\lambda }{d}\] Here, \[\lambda =600\,nm=6\times {{10}^{-7}}m\] \[d=0.1cm=1\times {{10}^{-3}}m\] \[\therefore \] \[{{\theta }_{10}}=\frac{10\times 6\times {{10}^{-7}}}{1\times {{10}^{-3}}}=60\times {{10}^{-4}}\] rad \[\Rightarrow \] \[{{\theta }_{10}}=0.006\] rad
You need to login to perform this action.
You will be redirected in
3 sec